使用Mathematica求数列的通项公式()。A.RSolve[a[n+1]==(2a[n]+3)/(a[n...
A.RSolve[a[n+1]==(2a[n]+3)/(a[n]+4),a[0]==0,a[n],n]
B.RSolve[{a_(n+1)==(2a_n+3)/(a_n+4),a_0==0},a_n,n]
C.RSolve[{a[n+1]==(2a[n]+3)/(a[n]+4),a[0]==0},a[n],n]
D.RSolve[{a[n+1]==(2a[n]+3)/(a[n]+4),a[0]==0},a[n]]