问答题

简答题 计算题:已知某正弦电流i1=15sin(314t-π/6),i2=20sin(314t+π/2),试求它们的相位差,并说明那个超前?

【参考答案】

Φ=Φ1-Φ2=(314t-π/6)-(314t+π/2)=-2π/3<0 
i2超前i12π/3,相位差2π/3