欢迎来到牛牛题库网 牛牛题库官网
logo

单项选择题

An analog signal m(t) with zero mean is a stationary process. Its frequency range is 0(Hz) ~ 8000(Hz) and its amplitude is uniformly distributed between -5(V) ~ +5(V). Then, the minimum Nyquist sampling frequency for this signal m(t) is f (Hz) , the average power is P (W). Assuming a uniform quantizer for this signal and the step size is D=0.04(V), the minimum number of quantization bits is R .
A、f=8000, P=25, R=8
B、f=16000, P=25/2, R=7
C、f=8000, P=25/3, R=9
D、f=16000, P=25/3, R=8

A.04(V),
B.
点击查看答案&解析
微信小程序免费搜题
微信扫一扫,加关注免费搜题

微信扫一扫,加关注免费搜题