Figure (a) is a practical circuit for the fluorescent lamp, whose equivalent circuit is shown in figure (b). The fluorescent lamp can be regarded as a resistor, and its parameters are 110V, 40W. The ballast is an inductor, the supply voltage is 220V, and the frequency is 50Hz. To ensure that the voltage across modulator tube is 110V. Find:① the current I=[填空1]A; ② the inductance L of the ballast =[填空2]H;     ③ the power factor cosφ1 of the circuit this moment =[填空3];   ④ if the power factor of the circuit is raised to1, the capacitance C need to be connected in parallel =[填空4]μF；  ⑤ the reactive power QC delivered by the capacitor =[填空5]Var.